E ExamMaster

AP EAPCET (Agriculture & Pharmacy) · Biology (Botany & Zoology)

Ecology and Environment

Organisms and populations, ecosystems, energy flow, biodiversity and conservation, and environmental issues.

Eight concepts. Ecology is the corner of NEET biology that actually computes — growth curves, the ten per cent law and the species–area line all carry arithmetic you can check — so nothing here is asserted that could instead be worked out or drawn.

  • AP EAPCET (Agriculture & Pharmacy)
  • Easy level
  • 8 concepts
  • 5 practice questions

1From organism to biosphere

Ecology asks its questions at six nested levels. An organism belongs to a population — all the individuals of one species in one area; populations of different species sharing that area make a community; the community together with the non-living surroundings, temperature and water and light and soil, is an ecosystem; ecosystems of one broad climatic type make a biome; and the sum of them all is the biosphere. The step that carries marks is community to ecosystem: adding the abiotic half is the whole difference.

At every level the abiotic factors set the terms, and an organism facing a hostile one has four options. It can regulate, holding its internal state steady whatever the outside does, as birds and mammals hold body temperature almost constant. It can conform, letting the internal state track the external, as most fish and invertebrates do. It can migrate away for the bad season. Or it can suspend — a seed, a bacterial spore, a hibernating bear, an aestivating snail. Regulation is the expensive option, which is why the great majority of animals are conformers.

Figure. Each level contains the one before it. Only the ecosystem box takes in the non-living surroundings — which is exactly why a community and an ecosystem are not the same thing, and why questions like to ask about that one boundary.

Four ways to meet a hostile abiotic factor
StrategyWhat the organism doesCost and example
RegulateHolds its internal conditions steady whatever the outside doesCostly in energy; birds and mammals
ConformLets its internal conditions track the external onesCheap; most fish, amphibians and invertebrates
MigrateLeaves for a favourable place while the season is badSiberian birds wintering at Keoladeo
SuspendHalts activity in a dormant stage until conditions returnSeeds, spores, hibernation, aestivation
A pond fish's body temperature rises and falls with the pond's. The fish is
  1. A conformer
  2. A regulator
  3. A partial regulator, as mammals are

Its internal temperature tracks the external one, and that is what conforming means. A regulator would hold its own temperature steady and pay for it in energy. Mammals are not partial regulators but full ones — partial regulation is the halfway case, where an animal regulates over a limited range of conditions and conforms outside it.

2What a population is made of

A population has properties no individual has: density, natality, mortality, sex ratio and age distribution. Over any interval its size obeys a balance sheet, N₁ = N₀ + (B + I) − (D + E), where B is births, D deaths, I immigrants and E emigrants. Only when B + I beats D + E does the population grow.

Natality and mortality are quoted per capita, per individual already present, so that populations of different sizes can be compared; their difference b − d is r, the intrinsic rate of natural increase. Notice what r leaves out — migration. A population whose births comfortably beat its deaths can still shrink, if enough individuals walk out.

The age distribution, drawn as an age pyramid, forecasts the interval after this one. A broad base of pre-reproductive individuals means growth is already committed whatever happens to this year's birth rate; a narrow base means decline is.

Figure. Two arrows in on the left, two out on the right. r is built from the natality and mortality pair alone, so a population can be losing individuals over the year while r stays comfortably positive.

A pond population's year

A pond holds 20 000 individuals on 1 January. Over the year there are 3000 births and 1500 deaths; 500 individuals arrive and 1000 leave.

  • b = 3000 / 200000.15 yr⁻¹
  • d = 1500 / 200000.075 yr⁻¹
  • r = b − d0.075 yr⁻¹
  • N₁ = 20000 + (3000 + 500) − (1500 + 1000)21 000
  • Realised change = 1000 / 200000.05 yr⁻¹

Pro tip. r says this population should be growing at 0.075 per head; it actually grew at 0.05, because 500 more individuals left than arrived. Whenever a question hands you migration figures as well as births and deaths, r is not the answer to "how fast did it grow".

Over one year a population records more births than deaths, yet ends the year smaller. The explanation must be
  1. Emigration exceeded immigration
  2. Its carrying capacity fell to zero
  3. Natality was quoted per capita rather than as a total

The balance sheet has four terms and only two of them are births and deaths, so net emigration is the only remaining way to lose individuals. A collapse in carrying capacity would act by raising deaths or suppressing births, which the given figures rule out; and quoting natality per capita changes the units of the rate, not the direction of the head count.

3Exponential growth and doubling time

Give a population unlimited resources and every individual contributes the same per-capita surplus, so dN/dt = rN and N_t = N₀eʳᵗ. The graph is the J-shaped curve: not merely rising but steepening, because each year's increment is proportional to a number that is itself growing.

The most useful thing to pull out of it is the doubling time, t_d = ln 2 / r ≈ 0.693/r. Notice what is missing from that expression: the starting size. A population of a hundred and a population of ten thousand, growing at the same r, take exactly the same time to double.

Figure. Both curves climb for ever; only the pace differs. Halving r does not halve the population — it doubles the doubling time, so the two marked points sit at the same height and 9.2 years becomes 18.5.

How fast is 0.075 per year?

The pond population of the previous concept has r = 0.075 yr⁻¹ and starts at 20 000. How long does it take to double, and where would unchecked growth put it after 20 years?

  • t_d = ln 2 / r = 0.693 / 0.0759.24 years
  • rt for t = 20 yr = 0.075 × 201.5
  • N = 20000 × e¹·⁵ = 20000 × 4.48289 600
  • Check: 20/9.24 = 2.164 doublings, 20000 × 2²·¹⁶⁴89 600

Pro tip. Two routes to the same figure, because 2^(t/t_d) and eʳᵗ are one function written two ways. If a question gives you a doubling time rather than an r, work in powers of two — three doublings is ×8, ten is ×1024.

Two populations grow exponentially at the same r, one starting at 100 individuals and one at 10 000. The time each takes to double is
  1. The same for both
  2. A hundred times longer for the larger one
  3. Shorter for the larger one, which has more breeders

t_d = ln 2 / r contains r and nothing else; the starting size cancels, because growth is per capita. The larger population does add far more individuals per year — that is what tempts you to the third option — but adding more and doubling faster are different claims, and the second option confuses population size with time.

4Logistic growth and carrying capacity

No habitat has unlimited resources, so the per-capita surplus is not a constant: it shrinks as the population fills the space. The Verhulst–Pearl logistic equation puts that shrinkage in one factor, dN/dt = rN(K − N)/K, with K the carrying capacity. While N is small the bracket is nearly 1 and growth is all but exponential; as N approaches K the bracket collapses towards zero and growth stops.

The result is the sigmoid, S-shaped curve, and the feature most asked about is not the plateau but the middle. The number of individuals added per unit time is greatest at N = K/2, where it equals rK/4 — small populations grow slowly because there are few breeders, nearly full ones because there is little left to grow into. It is also why a fishery is managed down to roughly half its carrying capacity rather than left untouched.

Figure. One population under two assumptions. The curves are indistinguishable at first; the dashed one keeps accelerating and runs off the top of the frame, while the solid one turns over at K/2 and settles under the ceiling without ever crossing it.

Where the growth is fastest

A population with r = 0.1 day⁻¹ lives where K = 500. Compare the number added per day at N = 50, at N = 250 and at N = 450.

  • Unlimited resources would give rN = 0.1 × 505.00 day⁻¹
  • rN(K − N)/K = 5.00 × 450/5004.50 day⁻¹
  • At N = 250: 0.1 × 250 × 250/50012.5 day⁻¹
  • At N = 450: 0.1 × 450 × 50/5004.50 day⁻¹
  • Predicted maximum rK/4 = 0.1 × 500 / 412.5 day⁻¹

Pro tip. N = 50 and N = 450 add exactly the same 4.50 a day — the curve is symmetric about K/2. At N = 50 the brake is barely touched (4.50 against an unrestrained 5.00); at N = 450 it is nearly full on, and the same rate now means something completely different.

In logistic growth, the number of individuals added per unit time is greatest when
  1. N is as small as possible
  2. N is half the carrying capacity
  3. N has just reached the carrying capacity

dN/dt = rN(K − N)/K multiplies a term that grows with N by one that shrinks with it, so it peaks in the middle, at rK/4. At very small N there are too few breeders for rN to amount to anything; at N = K the bracket is exactly zero, which is the definition of the plateau rather than of fast growth.

5Energy flow and the ten per cent law

Nutrients cycle; energy does not. Sunlight fixed by producers passes to herbivores, to carnivores, to top carnivores, and then out of the ecosystem as heat — one direction, no return, which is why an ecosystem needs a fresh delivery of sunlight every day while the atoms in it can be used over and over. Lindeman's rule of thumb is that roughly a tenth of the energy at one trophic level appears at the next. Measured efficiencies vary, but ten per cent is the figure NEET expects and the order of magnitude is right.

The other ninety per cent is not destroyed. Most is spent on respiration and leaves as heat, some departs unassimilated in faeces, and the rest is biomass that dies uneaten and enters the detritus food chain. Only what is both eaten and assimilated moves up.

Figure. Ten per cent moves right at each arrow; the ninety per cent heading downwards is respiration heat, faeces and uneaten biomass. Three transfers take 10 000 J down to 10 J, which is the real reason nothing lives above the fourth link.

Following 10 000 joules up the chain

Producers in a grassland fix 10 000 J. How much reaches the tertiary consumers, and what fraction of the original is that?

  • Primary consumers: 10% of 10 0001000 J
  • Secondary consumers: 10% of 1000100 J
  • Tertiary consumers: 10% of 10010 J
  • Fraction reaching the tertiary level: 10 / 10 0000.1%

Pro tip. A fifth link would be living on 1 J of the original 10 000. That, and not the size of the predators, is why food chains stop at four or five levels — there is simply nothing left to support another.

Which is true of a natural ecosystem?
  1. Both energy and nutrients are cycled and reused
  2. Energy flows one way while nutrients are cycled
  3. Nutrients flow one way while energy is cycled

A carbon atom in a leaf can end up in a leaf again, but a joule of sunlight, once degraded to heat, cannot be re-fixed, so energy must be resupplied by the sun continuously. The first option would make an ecosystem a perpetual-motion machine; the third has the two exactly the wrong way round.

6Ecological pyramids, and which ones invert

A pyramid stacks the trophic levels with the producers at the base and plots number, biomass or energy at each. The pyramid of energy can never be inverted: every transfer loses energy as heat, so each tier must be smaller than the one below it, and there is no exception anywhere.

Numbers and biomass carry no such guarantee, because they count standing crop rather than flow. One big tree is a single organism feeding thousands of insects, so the pyramid of numbers inverts. In the open sea the phytoplankton present at any instant weigh less than the zooplankton and fish they support, because they are eaten and replaced so fast, so the pyramid of biomass inverts. Both are entirely consistent with an upright pyramid of energy over the very same chain.

Pyramids also flatter an ecosystem in two ways worth remembering: they assume each species sits at exactly one trophic level, which a food web denies, and they leave the decomposers out altogether.

Figure. The same chain can give an upright pyramid of energy and an inverted pyramid of numbers or biomass, because the first measures a flow through time and the others measure a snapshot.

Which pyramid can invert, and when
PyramidUpright or invertedThe case that decides it
EnergyAlways uprightHeat is lost at every transfer, so no tier can exceed the one below
NumberUsually upright, sometimes invertedOne tree supporting thousands of insects and a few birds
Biomass, on landUprightThe standing crop of grass outweighs the grazers it feeds
Biomass, in the seaInvertedPhytoplankton are eaten and replaced fast, so little stands at any instant
A single large tree supports thousands of insects, which support a few birds. For this chain the pyramid of numbers and the pyramid of energy are, respectively
  1. Inverted and upright
  2. Both upright
  3. Upright and inverted

Counting heads gives one, then thousands, then a few — a base narrower than the tier above it, so the number pyramid inverts. Energy still falls at every transfer, as it must, so that pyramid stays upright. The third option is the one combination the second law actually forbids.

7Nutrient cycles: what comes back

Matter, unlike energy, is finite and therefore recycled. A biogeochemical cycle shuttles an element between a large reservoir and the living pool, and where the reservoir sits decides the cycle's character: carbon and nitrogen have atmospheric reservoirs and are called gaseous cycles, while phosphorus sits in rock and is sedimentary. That single fact is why phosphorus so often limits productivity — rock weathers slowly and there is no aerial shortcut.

Nitrogen shows the pattern most clearly. Nearly four-fifths of the atmosphere is N₂ and almost nothing can use it: the triple bond has to be broken — by nitrogen-fixing bacteria, by lightning, or industrially — before nitrogen enters biology at all.

Figure. Read the row left to right for the forward path, then the two long arrows for the returns: decay sends nitrogen back to ammonium, denitrification sends it all the way back to the air. Nitrification is drawn as one arrow but really runs via nitrite, as the steps say.

The nitrogen cycle, one turn

  1. FixationFree-living and symbiotic bacteria — Rhizobium in root nodules, Azotobacter in soil — reduce atmospheric N₂ to ammonia.
  2. NitrificationNitrosomonas oxidises ammonium to nitrite, then Nitrobacter takes the nitrite on to nitrate, the form roots take up most readily.
  3. Assimilation and decayPlants build nitrate into amino acids and proteins; when they and their consumers die, decomposers return the nitrogen to the soil as ammonium.
  4. DenitrificationIn waterlogged, oxygen-poor soil, bacteria such as Pseudomonas reduce nitrate back to N₂, and the atmosphere gets its nitrogen back.
Gaseous and sedimentary cycles
Cycle typeMain reservoirConsequence
Gaseous — carbon, nitrogenThe atmosphereRapid exchange with a global pool every ecosystem can draw on
Sedimentary — phosphorusRocks and sedimentsReleased only by weathering, so phosphorus frequently limits growth
Phosphorus cycles differently from carbon and nitrogen chiefly because
  1. Its main reservoir is rock rather than the atmosphere
  2. Plants have little use for it
  3. It is returned to the air by denitrifying bacteria

A sedimentary cycle has no significant gaseous phase, so phosphorus enters ecosystems only as fast as rock weathers — which is exactly why it so often limits growth. Plants need it heavily, for nucleic acids, ATP and membranes; and denitrification is a nitrogen process with no phosphorus counterpart at all.

8Biodiversity: measuring it and keeping it

Species richness is not spread evenly. It climbs steeply from the poles to the equator — the tropics have had a longer uninterrupted run without glaciation, more constant conditions and more solar energy — and it climbs with area, regularly enough to be written down.

Alexander von Humboldt's species–area relationship is a straight line on log–log axes: log S = log C + Z log A, with Z the slope. Within a region Z sits near 0.1 to 0.2 whatever the taxon, so doubling a species list takes roughly a hundredfold increase in area. Compare whole continents and Z climbs to 0.6–1.2, because you are then sampling separate evolutionary histories rather than a bigger slice of one.

What we protect follows from that. It is habitat area that is being lost, so conservation is first of all about keeping habitat intact. In-situ methods protect a species where it lives, with its whole community around it — national parks, wildlife sanctuaries, biosphere reserves, sacred groves, and the biodiversity hotspots that concentrate effort where endemism is highest, among them the Western Ghats, the Eastern Himalaya and Indo-Burma. Ex-situ methods take the organism out — zoos, botanical gardens, seed banks, cryopreserved gametes — and are the fallback for when the habitat has already gone.

Figure. Straight lines, because the relationship is a power law; both are drawn from a common intercept so that only the slope differs. The shallow line is what you meet inside a region — a hundredfold area for twice the species. The steep one appears only when whole continents are compared.

In-situ against ex-situ
ApproachWhat it actually protectsExamples
In-situThe species in its own habitat, community and interactions intactNational parks, wildlife sanctuaries, biosphere reserves, sacred groves
Ex-situThe species alone, removed to a managed settingZoos, botanical gardens, seed banks, cryopreservation of gametes

What Z is worth

Using log S = log C + Z log A, work out what multiplying the area by ten and by a hundred does to the species list — first within one region, where Z = 0.15, then across continents, where Z = 1.15.

  • Tenfold area: log S rises by Z log 10 = 0.15S × 10⁰·¹⁵
  • 10⁰·¹⁵1.41
  • Hundredfold area: 10^(2 × 0.15) = 10⁰·³⁰2.00
  • Across continents, tenfold area: 10¹·¹⁵14.1

Pro tip. Ten times the area buys only forty per cent more species inside one region. Run it backwards and the same slope is unforgiving: shrink a reserve to a tenth of its size and you keep about seventy per cent of its species, then the next tenth costs you the same fraction again.

A sacred grove, a zoo and a seed bank all preserve species. Which of them is in-situ conservation?
  1. The sacred grove
  2. The zoo
  3. The seed bank

In-situ means the organism stays in its own habitat, with the community and the selection pressures it evolved under, and a sacred grove is a patch of exactly that, protected by custom. A zoo and a seed bank both remove the organism from its habitat, which is what ex-situ means; neither preserves the interactions the species is part of.

Notes

  • Ecological levels rise from organism → population → community → ecosystem → biome → biosphere, and adaptations help organisms cope with abiotic factors.
  • Population growth is exponential (\frac{dN}{dt}=rN, J-shaped) under unlimited resources and logistic (\frac{dN}{dt}=rN\frac{K-N}{K}, S-shaped) with a carrying capacity K.
  • In an ecosystem energy flows unidirectionally through trophic levels, with only about 10% transferred at each step (Lindeman's 10% law).
  • Biogeochemical cycles (carbon, nitrogen, phosphorus) recycle matter, and ecological pyramids show trophic structure (the pyramid of energy is always upright).
  • Biodiversity and conservation: hotspots are protected by in-situ methods (national parks, sanctuaries) and ex-situ methods (zoos, seed banks); pollution and global warming are major issues.

Formulas

  • Exponential growth: \frac{dN}{dt}=rN (J-shaped curve)
  • Logistic growth: \frac{dN}{dt}=rN\left(\frac{K-N}{K}\right) (S-shaped, K = carrying capacity)
  • Lindeman's 10% law: ~10% of energy passes to the next trophic level
  • Species-area relationship: \log S=\log C+Z\log A
  • Pyramid of energy is always upright; number/biomass pyramids can be inverted

Exam traps & shortcuts

  • Because energy flow follows the 10% law, food chains rarely exceed 4–5 trophic levels.
  • The pyramid of energy is always upright, but pyramids of number and biomass can be inverted (e.g. a single tree, or an ocean).
  • In-situ conservation is on-site (national parks, biosphere reserves); ex-situ is off-site (zoos, botanical gardens, seed banks).

Reference tables

Every line here should be reconstructible from the concept it came from, not merely recalled.

Formula sheet
QuantityRelationWatch for
Population balanceN₁ = N₀ + (B + I) − (D + E)Migration is half the sheet
Intrinsic rate of increaser = b − dBuilt from births and deaths only
Exponential growthdN/dt = rN, N_t = N₀eʳᵗJ-shaped, and there is no ceiling
Doubling timet_d = ln 2 / r ≈ 0.693/rContains no N₀, so size is irrelevant
Logistic growthdN/dt = rN(K − N)/KS-shaped; N approaches K, never passes it
Fastest logistic growthAt N = K/2, dN/dt = rK/4Not at K, where the rate is zero
Lindeman's lawAbout 10% passes to the next levelCaps food chains at four or five links
Species–arealog S = log C + Z log AZ ≈ 0.1–0.2 in a region, 0.6–1.2 across continents
Pyramid of energyAlways uprightNumber and biomass may invert

Four issues the paper returns to. Each has a driver and a consequence, and the options routinely swap the two.

Environmental issues at a glance
IssueDriverWhat it does
Global warmingCarbon dioxide, methane, nitrous oxide and CFCs trapping outgoing infra-redRising mean temperature, retreating ice, shifting species ranges
Ozone depletionChlorine released from CFCs breaking down stratospheric ozoneMore UV-B at the surface: skin cancer, cataract, inflammation of the cornea
EutrophicationNitrogen and phosphorus running off into still or slow waterAlgal bloom, then decay that raises BOD and strips the dissolved oxygen
BiomagnificationFat-soluble, non-degradable pollutants such as DDT entering a food chainConcentration rises at each trophic level, so top consumers are hit hardest

Recap

Read only this the night before.

Levels
Community plus the abiotic surroundings is an ecosystem. Regulate, conform, migrate or suspend — and most animals conform, because regulating costs energy.
Balance sheet
N₁ = N₀ + (B + I) − (D + E), and r = b − d ignores migration entirely. A population can shrink with r positive.
Two curves
J-shaped: dN/dt = rN, doubling in ln 2 / r whatever N₀ is. S-shaped: dN/dt = rN(K − N)/K, fastest at K/2 where it equals rK/4.
Ten per cent
10 000 → 1000 → 100 → 10 J. Energy flows one way, nutrients cycle, and four or five links is the limit.
Pyramids
Energy always upright. Numbers invert for a single tree; biomass inverts in the sea. Decomposers appear in none of them.
Cycles
Carbon and nitrogen gaseous, phosphorus sedimentary. Nitrogen: fixation, nitrification via nitrite, assimilation, ammonification, denitrification.
Biodiversity
log S = log C + Z log A, with Z ≈ 0.15 in a region and 0.6–1.2 across continents. In-situ keeps the habitat, ex-situ keeps only the organism.

Practise Ecology and Environment

Reading is free and needs no account. Practice, mocks and progress live in the app.

  • 5 exam-style questions on this topic, with explanations
  • A 5-question practice set that ends the chapter
  • Timed mocks scored with the real marking scheme
  • Readiness tracked per topic, kept on your device
Continue with Google — freeNo card, no trial. Works offline once installed.